Using 2D DFT Transformation in Intel IPP 8.2 (Image DFT)

Hello,

I'm comparing the results of the magnitude of DFT Transform of Intel DFTFwd to MATLAB's fft.

The input is Real Image in 32fC1 format.
The code snippet is:

int sizeSpec;
int sizeInit;
int sizeBuffer;
/// get sizes for required buffers
	IppStatus status = ippiDFTGetSize_R_32f(mI.size_, IPP_FFT_DIV_FWD_BY_N, ippAlgHintNone,&sizeSpec, &sizeInit, &sizeBuffer);

    /// allocate memory for required buffers
    IppiDFTSpec_R_32f* pMemSpec = (IppiDFTSpec_R_32f*)ippMalloc(sizeSpec);

Ipp8u* pMemInit   = NULL;
Ipp8u* pMemBuffer = NULL;
    if (sizeInit > 0)
         pMemInit = (Ipp8u*)ippMalloc(sizeInit);

    if (sizeBuffer > 0)
         pMemBuffer = (Ipp8u*)ippMalloc(sizeBuffer);

    /// initialize DFT specification structure
    status = ippiDFTInit_R_32f(mI.size_, IPP_FFT_DIV_FWD_BY_N, ippAlgHintNone, pMemSpec, pMemInit);

    /// free initialization buffer
    if (sizeInit > 0)
        ippFree(pMemInit);

    /// perform forward DFT to put source data to frequency domain
status = ippiDFTFwd_RToPack_32f_C1IR(mI, mI.bytes_step_[0], pMemSpec, pMemBuffer);
status = ippiMagnitudePack_32f_C1R(mI, mI.bytes_step_[0], mI, mI.bytes_step_[0], mI.size_);
//status = ippiPhasePack_32f_C1R(mI, mI.bytes_step_[0], mI, mI.bytes_step_[0], mI.size_);

/// ...

    /// free buffers
    if (sizeBuffer > 0)
        ippFree(pMemBuffer);

    ippFree(pMemSpec);
}

The result is different from MATLAB's (In the bottom right quadrant).
I also tried the phase and got it is different as well (Again, all perfect but certain quadrant).

Any idea what's happening?
Have I missed something?

Thank You.